Sunday, June 26, 2022

1875. Same Centers

 1. ) Let $H$ and $N_a$ be the orthocenter and Nagel's point of $ABC$. Let $X,Y,Z$ be the projections of $N_a$ on $HA, HB, HC$.

$ABC$ and $XYZ$ have same incenter.

2.) Let $K$ be the symmedian point of $ABC$. Let $X,Y,Z$ be the projections of $K$ on perpendicular bisectors of $BC, CA, AB$
** $ABC$ and $XYZ$ have same centroid.

Friday, June 24, 2022

1874. A Family Of Conics Centered at X(5)-NPC Center (Part 2)

1873. A Family Of Conics Centered at X(5)-NPC center

 Lat ABC be an acute angled triangle and P be a point.

A1B1C1-cevian triangle of P and A2B2C2-circumcevian triangle of P.
Oba=Circumcenter of (BA1A2),  Oca=Circumcenter of (CA1A2).
Circle through the points A2,Oba, Oca intersects the BC at A3, A4.
Define B3,B4,C3,C4 cyclically.

*A3, A4, B3, B4, C3, C4 lie on same conic. For all P, center of conic is X(5)-NPC center.
Are there any remarkable properties of perspectors of these family of conics?

Sunday, June 19, 2022

1871. Collinear Points

 Let I=X(1)- Incenter of ABC. P be a point on Circumcircle of ABC with first barycentric (a^2(x-y)(x-z):...:...)  Pa,Pb,Pc inverse of P in the circles BIC, CIA, AIB resp.

* I, Pa, Pb, Pc lie on same line. 
** Trilinear pole of  line has first barycentric (a (x-y)(x-z):...:...).
Some pairs (P,Q)=(Xi, Xj) where Q is trilinear pole of the line.
{(74, 2349), (98,1821), (99, 799), (100,190)....}

Wednesday, June 8, 2022

1866. A Property Of Kiepert Circum Hyperbola

 This problem is inspired from #5175 by Tran Quang Hung.


Let P,Q be two points on Kiepert hyperbola of ABC. Circles APQ, BPQ, CPQ intersects the Kiepert hyperbola of ABC at A', B',C' resp.
R=X(2)-Centroid of of A'B'C' lies on Kiepert hyperbola of ABC.
So we have a transformation T, T(P,Q)->R, Let's show it with * operation. Then we have:
P*Q=R, P*R=Q, Q*R=P

1987. Circumcenter On Euler Line

 Let H=X(4)-Orthocenter of ABC. A 1 B 1 C 1 cevian triangle of H. B1 A , C1 A are reflections of B1, C1 on A. L A , line through B1 A , C1...