Thursday, June 30, 2022
Wednesday, June 29, 2022
Sunday, June 26, 2022
1875. Same Centers
1. ) Let and be the orthocenter and Nagel's point of . Let be the projections of on .
* and have same incenter.2.) Let be the symmedian point of . Let be the projections of on perpendicular bisectors of
** and have same centroid.
** and have same centroid.
Friday, June 24, 2022
1873. A Family Of Conics Centered at X(5)-NPC center
Lat ABC be an acute angled triangle and P be a point.
A1B1C1-cevian triangle of P and A2B2C2-circumcevian triangle of P.Oba=Circumcenter of (BA1A2), Oca=Circumcenter of (CA1A2).
Circle through the points A2,Oba, Oca intersects the BC at A3, A4.
Define B3,B4,C3,C4 cyclically.
*A3, A4, B3, B4, C3, C4 lie on same conic. For all P, center of conic is X(5)-NPC center.
Are there any remarkable properties of perspectors of these family of conics?
Wednesday, June 22, 2022
Sunday, June 19, 2022
1871. Collinear Points
Let I=X(1)- Incenter of ABC. P be a point on Circumcircle of ABC with first barycentric (a^2(x-y)(x-z):...:...) Pa,Pb,Pc inverse of P in the circles BIC, CIA, AIB resp.
* I, Pa, Pb, Pc lie on same line.** Trilinear pole of line has first barycentric (a (x-y)(x-z):...:...).
Some pairs (P,Q)=(Xi, Xj) where Q is trilinear pole of the line.
{(74, 2349), (98,1821), (99, 799), (100,190)....}
Thursday, June 16, 2022
Wednesday, June 15, 2022
Sunday, June 12, 2022
Friday, June 10, 2022
Wednesday, June 8, 2022
1866. A Property Of Kiepert Circum Hyperbola
This problem is inspired from #5175 by Tran Quang Hung.
Let P,Q be two points on Kiepert hyperbola of ABC. Circles APQ, BPQ, CPQ intersects the Kiepert hyperbola of ABC at A', B',C' resp.
R=X(2)-Centroid of of A'B'C' lies on Kiepert hyperbola of ABC.
So we have a transformation T, T(P,Q)->R, Let's show it with * operation. Then we have:
P*Q=R, P*R=Q, Q*R=P
Tuesday, June 7, 2022
Saturday, June 4, 2022
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1987. Circumcenter On Euler Line
Let H=X(4)-Orthocenter of ABC. A 1 B 1 C 1 cevian triangle of H. B1 A , C1 A are reflections of B1, C1 on A. L A , line through B1 A , C1...