Showing posts with label Perspective Triangles. Show all posts
Showing posts with label Perspective Triangles. Show all posts
Monday, March 10, 2025
Tuesday, July 16, 2024
Thursday, May 16, 2024
Tuesday, February 6, 2024
Sunday, July 16, 2023
1955. A Construction For the Perspector Of 2nd Lemoine Circle
Let K=X(6)-Symmedian point of ABC. Antiparallel from K to BC intersect the AB, AC at Ac, Ab resp.
Define Ba, Bc, Ca, Cb cyclically.
KA: Antipode of K respect to circle (KBaCa). Define KB, KC cyclically.
* ABC and KAKB,KC are perspective triangles. Perspector is X(3527) = ISOGONAL CONJUGATE OF X(631)=perspector of 2nd Lemoine circle
Monday, March 27, 2023
Saturday, May 21, 2022
1857. Isogonal Curves and Isogonal Perspectors
1.) Let P be a point and A1B1C1 cevian triangle of P.
A2: inverse of A1 in the circle PBC. Define B2, C2 cyclically.*ABC and A2B2C2 are perspective if P lies on a curve C passing through X(2)-centroid, X(4)-Orthocenter and X(13)-1st Fermat-Toricelli point.
For X(2)-centroid, X(4)-Orthocenter and X(13)-1st Fermat-Toricelli point perspectors of ABC and A2B2C2 are X(524), X(403) and X(36211).
2.) Let P be a point and A1B1C1 circumcevian triangle of P.
A2: inverse of A1 in the circle PBC. Define B2, C2 cyclically.
**ABC and A2B2C2 are perspective if P lies on a curve C* passing through X(6)-symmedian point, X(3)-Circumcenter and X(15)-1st Isodynamic point.
For X(6)-symmedian point, X(3)-Circumcenter and X(15)-1st Isodynamic point perspectors of ABC and A2B2C2 are X(111), X(5504) and X(36209).
*** Do curves C and C* defined in problem 1 and 2 are isogonal conjugates?
**** Interestingly perspectors in problem 1 and perspectors in problem 2 are isogonal conjugate points.
Does this property valid for all perspectors?
Thursday, May 5, 2022
Sunday, May 1, 2022
Saturday, April 30, 2022
Wednesday, April 27, 2022
1832. Inverted Triangles and Circumcenters On Euler Line
Let ABC be a triangle and A1B1C1 is perspective with ABC at a point P and homothetic to ABC.
A2 is inversion of A1 respect to circumcircle of ABC. Define B2, C2 cyclically.
* Circumcenter of A2B2C2 lies on the line OP.
Application. Let P be a point on Euler line of ABC. A1,B1,C2 midpoints of AP, BP, CP resp.
A2 is inversion of A1 respect to circumcircle of ABC. Define B2, C2 cyclically.
** O',Circumcenter of A2B2C2 lies on the Euler Line of ABC.
For P=X(2), O'=X(33532)
For P=X(5), O'=X(?)
For P=X(20), O'=X(12084)
Monday, April 4, 2022
Sunday, April 3, 2022
Sunday, March 27, 2022
Wednesday, March 23, 2022
Wednesday, January 5, 2022
Friday, July 23, 2021
Thursday, July 1, 2021
Sunday, June 6, 2021
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Dedicated to Francisco Javier García Capitán on the occasion of his birthday.











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