Thursday, April 8, 2021

1684. P-Cevian Orthiac Triangle of Isodynamic Points

2 comments:

  1. It is also true for X(16).
    With X(15): Barycentric coordinates of center of A1B1C1:
    3*(15*R^2-2*SA-3*SW)*S^4+3*(6*(3*SA+SW)*R^4+3*(SA^2+SB*SC-4*SW^2)*R^2-(4*SA^2-15*SB*SC-5*SW^2)*SW)*S^2+3*(3*R^2+SW)*SB*SC*SW^2-S*sqrt(3)*(3*(SA-SW)*(18*R^4*SA-3*(5*SA+SW)*R^2*SW-(2*SA-SW)*SW^2)+(-4*(3*SA+7*SW)*R^2+9*SA^2-21*SB*SC-15*SW^2)*S^2+7*S^4) : :
    Search: {-1.04954528312553, -1.84051943902886, 5.39927576267317}

    For X(16): Just change S->-S.
    Search: {0.254903395453504, -0.115343339102474, 3.60286984184187}

    Unfortunately, no relations with any center in ETC

    ReplyDelete
  2. Thank you very much Sir Lozada. Best regards

    ReplyDelete

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