Showing posts with label X(101). Show all posts
Showing posts with label X(101). Show all posts

Saturday, March 5, 2022

1807. Circles Through Isodynamic Points

 Let S=X(15)-1st Isodynamic point of ABC.

Sa,Sb,Sc are X(100) points of SBC, SCA, SAB resp.

*S,Sa,Sb,Sc lie on same circle.

** If Sa,Sb,Sc are X(101) points of SBC, SCA, SAB resp. again S,Sa,Sb, Sc lie on same circle.

1996. A Collinearity