1807. Circles Through Isodynamic Points

 Let S=X(15)-1st Isodynamic point of ABC.

Sa,Sb,Sc are X(100) points of SBC, SCA, SAB resp.

*S,Sa,Sb,Sc lie on same circle.

** If Sa,Sb,Sc are X(101) points of SBC, SCA, SAB resp. again S,Sa,Sb, Sc lie on same circle.