For P=X(5)-NPC center and P=X(6) symmedian point, X is non-ETC point. If P=X(6), X has first barycentric: (a^4 (b^2 -c^2)^2 (-3 a^6 + b^6 + 7 b^4 c^2 + 7 b^2 c^4 + c^6 + 7 a^4 (b^2 + c^2) - a^2 (5 b^4 + 14 b^2 c^2 + 5 c^4)):...:...)
Let H=X(4)-Orthocenter of ABC. A 1 B 1 C 1 cevian triangle of H. B1 A , C1 A are reflections of B1, C1 on A. L A , line through B1 A , C1...
For P=X(5)-NPC center and P=X(6) symmedian point, X is non-ETC point. If P=X(6), X has first barycentric: (a^4 (b^2 -c^2)^2 (-3 a^6 + b^6 + 7 b^4 c^2 + 7 b^2 c^4 + c^6 + 7 a^4 (b^2 + c^2) - a^2 (5 b^4 + 14 b^2 c^2 + 5 c^4)):...:...)
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