Tuesday, January 12, 2021

1629.

3 comments:

  1. Cyclologic centers:
    For P=X(17): X(14) & X(3479)
    For P=X(18): X(13) & X(3480)

    ReplyDelete
  2. Cyclologic centers:
    For P=X(17): X(14) & X(3479)
    For P=X(18): X(13) & X(3480)

    ReplyDelete
  3. Radius of circles = sqrt(SW-sqrt(3)*S)/2
    With P=X(17): A'B'C' is the 2nd half-diamonds triangles
    With P=X(18): A'B'C' is the 1st half-diamonds triangles

    Explanation: Find three points A', B', C' such that AB'C', BC'A' and CA'B' are equilateral. The problem has two solutions and the triangles A'B'C' and A"B"C" (2nd solution) are the 1st and 2nd half-diamond triangles.

    ReplyDelete

1988. Circumcenters On Euler Line

  Let ABC be a triangle with P, Q are two points on Euler line of ABC. A',B',C' are inverse images of A,B,C through circle diame...