Same is true if we use Brocard axis of triangles instead of Euler lines.
https://bernard-gibert.pagesperso-orange.fr/Exemples/k001.html, Property 20.
For P=X(13), OAOBOC is equilateral. It's the reflection of Napoleon Equilateral triangle on its center.
https://www.journal-1.eu/2021/Abdilkadir%20Altintas.%20Congruent%20Circles%20on%20Locus%20Problems,%20pp.%2092-96..pdf
Let ABC be a triangle with P, Q are two points on Euler line of ABC. A',B',C' are inverse images of A,B,C through circle diame...
Same is true if we use Brocard axis of triangles instead of Euler lines.
ReplyDeletehttps://bernard-gibert.pagesperso-orange.fr/Exemples/k001.html, Property 20.
ReplyDeleteFor P=X(13), OAOBOC is equilateral. It's the reflection of Napoleon Equilateral triangle on its center.
ReplyDeletehttps://www.journal-1.eu/2021/Abdilkadir%20Altintas.%20Congruent%20Circles%20on%20Locus%20Problems,%20pp.%2092-96..pdf
ReplyDelete