Thursday, March 4, 2021

1672. Parabologic Triangles

2 comments:

  1. Let DEF be orthic triangle. K_A, K_B,K_C symmedian points of AFE, BFD, CDE resp. ABC is parabologiv to K_AK_BK_C, parabology center is X(6) symmedian point of ABC.

    ReplyDelete
  2. https://artofproblemsolving.com/community/u426945h2503666p21149968

    ReplyDelete

1988. Circumcenters On Euler Line

  Let ABC be a triangle with P, Q are two points on Euler line of ABC. A',B',C' are inverse images of A,B,C through circle diame...