Instead of Steiner points, if we use X(110) centers, fixed perspector of ABC and A1B1C1 is X(54)-Kosnita point.
The other points satisfyind same property are X(107) and X(476)-Tixier point.
If we use X(5)-NPC centers, AA1, BB1,CC1 are parallel lines.
Let ABC be a triangle with P, Q are two points on Euler line of ABC. A',B',C' are inverse images of A,B,C through circle diame...
Instead of Steiner points, if we use X(110) centers, fixed perspector of ABC and A1B1C1 is X(54)-Kosnita point.
ReplyDeleteThe other points satisfyind same property are X(107) and X(476)-Tixier point.
ReplyDeleteIf we use X(5)-NPC centers, AA1, BB1,CC1 are parallel lines.
ReplyDelete