Geometri Günlüğü
Thursday, March 11, 2021
1676. Congruent Circles
1 comment:
Dr. Abdilkadir Altıntaş
March 11, 2021 at 12:44 PM
For P=X(15), OAOBOC is equilateral.
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1995. Circumcenter at Midpoint of BC
1949. On Fermat's Configuration
1658. Brocard Points-Orthologic Triangles
1983. A Circumcircle Through Circumcenter of ABC
For P=X(15), OAOBOC is equilateral.
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