Wednesday, May 12, 2021

1698. Concurrent Circles and X(502)

2 comments:

  1. The circle (NaNbNc) which is centered at X(5), has radius
    squared R^2/4 - (abc s r)/(2S^2), and passes through X(k), k ∈ {10, 502, 946}.

    Elias M. Hagos

    ReplyDelete
  2. X(502)={(b + c) (-a^3 - a^2 (b + c) + (b - c) (b + c)^2 +
    a (b^2 - b c - c^2)) (a^3 + a^2 (b + c) + (b - c) (b + c)^2 +
    a (b^2 + b c - c^2)), (a + c) (a^3 +
    a^2 (b + c) + (b - c) (b + c)^2 + a (b^2 + b c - c^2)) (a^3 -
    b^3 - b^2 c - b c^2 - c^3 + a^2 (b + c) -
    a (b^2 + b c + c^2)), (a + b) (a^3 +
    a^2 (b + c) - (b - c) (b + c)^2 + a (-b^2 + b c + c^2)) (a^3 -
    b^3 - b^2 c - b c^2 - c^3 + a^2 (b + c) - a (b^2 + b c + c^2))}

    ReplyDelete

1987. Circumcenter On Euler Line

 Let H=X(4)-Orthocenter of ABC. A 1 B 1 C 1 cevian triangle of H. B1 A , C1 A are reflections of B1, C1 on A. L A , line through B1 A , C1...