A similar locus for K007-Lucas Cubic:Let $L=X_{20}$ -Delongchamp's point of $ABC$ and $P$ be a point on K007-Lucas Cubic of $ABC$. $DEF$-Cevian triangle of $P$.Perpendicular to $LP$ at $P$ intersects the $BC$ and $EF$ at $X,Y$ respectively.\\ *$\frac{XP}{PY}=2$ \\
Let H=X(4)-Orthocenter of ABC. A 1 B 1 C 1 cevian triangle of H. B1 A , C1 A are reflections of B1, C1 on A. L A , line through B1 A , C1...
A similar locus for K007-Lucas Cubic:
ReplyDeleteLet $L=X_{20}$ -Delongchamp's point of $ABC$ and $P$ be a point on K007-Lucas Cubic of $ABC$. $DEF$-Cevian triangle of $P$.
Perpendicular to $LP$ at $P$ intersects the $BC$ and $EF$ at $X,Y$ respectively.\\
*$\frac{XP}{PY}=2$ \\