Wednesday, April 27, 2022

1832. Inverted Triangles and Circumcenters On Euler Line

 Let ABC be a triangle and A1B1C1 is perspective with ABC at a point P and homothetic to ABC.

A2 is inversion of A1 respect to circumcircle of ABC. Define B2, C2 cyclically.

* Circumcenter of A2B2C2 lies on the line OP.

Application. Let P be a point on Euler line of ABC. A1,B1,C2 midpoints of AP, BP, CP resp.

A2 is inversion of A1 respect to circumcircle of ABC. Define B2, C2 cyclically.

** O',Circumcenter of A2B2C2 lies on the Euler Line of ABC.

For P=X(2), O'=X(33532)

For P=X(5), O'=X(?)

For P=X(20), O'=X(12084)

Monday, April 25, 2022

1831. ConConic Triangles

 Let P be a point and A1B1C1 cevian triangle of P.

ta= tangent to circumcircle of A1B1C1 at A1. Define tb, tc cyclically.
Let A2B2C2 triangle bounded by lines ta, tb, tc.

*A,B,C, A2,B2,C2 lie on same conic.
** For P=X(2), Center of the conic is X(15449)-CENTER OF THE X(2)-ALTINTAS HYPERBOLA.
*** Which is the center of the conic for some triangle centers?

Tuesday, April 12, 2022

1829. Constructions For X(14790) and X(18569)

 1. Let O=X(3) circumcenter of ABC. Ha, Hb, Hc orthocenters of OBC, OCA, OAB resp.

La=Antiparallel from Ha to BC. Define Lb, Lc cyclically.
Let A1B1C1 triangle bounded by lines La,Lb,Lc.
* Orthocenter of A1B1C1 lies on Euler line of ABC. Its X(14790)= Conjugate-Couple of X(22) In the Range In Involution {X(2),X(5)}, {X(3),X(4)}.

2.Let H=X(4) orthocenter of ABC. Oa, Ob, Oc circumcenters of HBC, HCA, HAB resp.
La=Antiparallel from Oa to BC. Define Lb, Lc cyclically.
Let A1B1C1 triangle bounded by lines La,Lb,Lc.
* Circumcenter of A1B1C1 lies on Euler line of ABC. Its X(18569)= Ehrmann-Side-Ehrmann-Vertex Similarity Image of X(382).

1987. Circumcenter On Euler Line

 Let H=X(4)-Orthocenter of ABC. A 1 B 1 C 1 cevian triangle of H. B1 A , C1 A are reflections of B1, C1 on A. L A , line through B1 A , C1...