Circle is valid for pedal triangle of any point P.Center of circle is midpoint of P and P*,where P* is isogonal conjugate of P. (possibly known fact).
Let H=X(4)-Orthocenter of ABC. A 1 B 1 C 1 cevian triangle of H. B1 A , C1 A are reflections of B1, C1 on A. L A , line through B1 A , C1...
Circle is valid for pedal triangle of any point P.
ReplyDeleteCenter of circle is midpoint of P and P*,where P* is isogonal conjugate of P. (possibly known fact).