Monday, February 1, 2021

1642.

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3 comments:

  1. Dr. Abdilkadir AltıntaşMay 14, 2021 at 6:37 PM

    ** Ka,Kb,Kc,X(1),X(484) are collinear.

    ReplyDelete
  2. AnonymousJuly 2, 2025 at 6:00 PM

    Circle (AKbKc), (BKcKa), (CKaKb) concur at the circumcircle of ABC.

    ReplyDelete
  3. AnonymousJuly 2, 2025 at 6:15 PM

    Circles (AKbKc), (BKcKa), (CKaKb) concur at a point in the circumcircle.

    ReplyDelete

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1995. Circumcenter at Midpoint of BC