For P=X(3)-Circumcenter, center of conic is X(6523)=SS(a->SASB) of X(3).
Let H=X(4)-Orthocenter of ABC. A 1 B 1 C 1 cevian triangle of H. B1 A , C1 A are reflections of B1, C1 on A. L A , line through B1 A , C1...
For P=X(3)-Circumcenter, center of conic is X(6523)=SS(a->SASB) of X(3).
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