For P=X(3)-Circumcenter, center of conic is X(6523)=SS(a->SASB) of X(3).
Let ABC be a triangle with P, Q are two points on Euler line of ABC. A',B',C' are inverse images of A,B,C through circle diame...
For P=X(3)-Circumcenter, center of conic is X(6523)=SS(a->SASB) of X(3).
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