Similar and symmetric Triangles ABC is cyclologic to A3B3C3 at X(110) of ABC. Similarly A3B3C3 cyclologic to ABC at X(110) of A3B3C3. (X(20) of ABC). Euler line of ABC passes through X(110) of A3B3C3 and Euler line of A3B3C3 passes through X(110) of ABC.
Similar and symmetric Triangles
ReplyDeleteABC is cyclologic to A3B3C3 at X(110) of ABC.
Similarly A3B3C3 cyclologic to ABC at X(110) of A3B3C3. (X(20) of ABC).
Euler line of ABC passes through X(110) of A3B3C3 and Euler line of A3B3C3 passes through X(110) of ABC.