Conjecture is true. X_6(PQR) = (SA+SB+SC) X + S (H - X(3)) ,where H is the orthocenter, X(3) the circumcenter of ABC and S is twice the area of ABC.Elias M. Hagos
Conjecture is true. X_6(PQR) = (SA+SB+SC) X + S (H - X(3)) ,
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Elias M. Hagos