Friday, April 23, 2021

1690. An Inspiration of Mehmet Şahin's Problem

1 comment:

  1. Conjecture is true. X_6(PQR) = (SA+SB+SC) X + S (H - X(3)) ,

    where H is the orthocenter, X(3) the circumcenter of ABC and S is twice the area of ABC.

    Elias M. Hagos

    ReplyDelete

1987. Circumcenter On Euler Line

 Let H=X(4)-Orthocenter of ABC. A 1 B 1 C 1 cevian triangle of H. B1 A , C1 A are reflections of B1, C1 on A. L A , line through B1 A , C1...