Line BcCb is perpendicular bisector of BC.
let A1B1C1 be the CircumCevian triangle of X(15). A',B',C' are the antipodes of A1,B1,C1 on the circumcircle respectively
Line BcCb is perpendicular bisector of BC.
ReplyDeletelet A1B1C1 be the CircumCevian triangle of X(15). A',B',C' are the antipodes of A1,B1,C1 on the circumcircle respectively
ReplyDelete