Line BcCb is perpendicular bisector of BC.
let A1B1C1 be the CircumCevian triangle of X(15). A',B',C' are the antipodes of A1,B1,C1 on the circumcircle respectively
Let ABC be a triangle with P, Q are two points on Euler line of ABC. A',B',C' are inverse images of A,B,C through circle diame...
Line BcCb is perpendicular bisector of BC.
ReplyDeletelet A1B1C1 be the CircumCevian triangle of X(15). A',B',C' are the antipodes of A1,B1,C1 on the circumcircle respectively
ReplyDelete